# pg_field_type_oid

(PHP 5 >= 5.1.0, PHP 7, PHP 8)

pg_field_type_oid — Returns the type ID (OID) for the corresponding field number

### 说明

pg_field_type_oid(PgSql\Result `$result`, int `$field`): string|int

pg_field_type_oid() returns an integer containing the OID of the base type of the given `field` in the given `result` instance.

You can get more information about the field type by querying PostgreSQL's `pg_type` system table using the OID obtained with this function. The PostgreSQL format_type() function will convert a type OID into an SQL standard type name.

> 注意:

> If the field uses a PostgreSQL domain (rather than a basic type), it is the OID of the domain's underlying type that is returned, rather than the OID of the domain itself.

### 参数

`result`

  PgSql\Result 实例，由 pg_query()、pg_query_params() 或者 pg_execute()（等）返回。

`field`

  Field number, starting from 0.

### 返回值

The OID of the field's base type.

### 更新日志

版本 | 说明
--- | ---
8.1.0 | 现在 `result` 参数接受 PgSql\Result 实例，之前接受 resource。

### 示例

示例 #1 Getting information about fields

`<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
// Assume 'title' is a varchar type
$res = pg_query($dbconn, "select title from authors where author = 'Orwell'");
echo "Title field type OID: ", pg_field_type_oid($res, 0);
?>`

以上示例会输出：

    Title field type OID: 1043

### 参见

- pg_field_type() - 返回相应字段编号的类型名称
- pg_field_prtlen() - 返回打印的长度
- pg_field_name() - 返回字段名

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